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Find the speed required to throw a ball straight up and have it return 6 seconds later. Neglect air resistance?
got a exam in a hour on this stuff just if you could please help
Consider the first three seconds.
v=u+at
Substitute v=0, a=-9•8, t=3.
0 = u - 9•8*3
u = 29•4
The next three seconds will be the same but in reverse.
So the answer is 29•4 metres per second.
I hope this helps.
P.S. For a speedier response, try asking questions like this in the maths/science section.
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